72x^2-96x+32=0

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Solution for 72x^2-96x+32=0 equation: 



72x^2-96x+32=0

a = 72; b = -96; c = +32;
Δ = b2-4ac
Δ = -962-4·72·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{96}{144}=2/3$

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